z^2-(1+a)(1+i)z+(a+a^2)i=0

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Solution for z^2-(1+a)(1+i)z+(a+a^2)i=0 equation:


Simplifying
z2 + -1(1 + a)(1 + i) * z + (a + a2) * i = 0

Reorder the terms for easier multiplication:
z2 + -1z(1 + a)(1 + i) + (a + a2) * i = 0

Multiply (1 + a) * (1 + i)
z2 + -1z(1(1 + i) + a(1 + i)) + (a + a2) * i = 0
z2 + -1z((1 * 1 + i * 1) + a(1 + i)) + (a + a2) * i = 0
z2 + -1z((1 + 1i) + a(1 + i)) + (a + a2) * i = 0
z2 + -1z(1 + 1i + (1 * a + i * a)) + (a + a2) * i = 0
z2 + -1z(1 + 1i + (1a + ai)) + (a + a2) * i = 0

Reorder the terms:
z2 + -1z(1 + 1a + ai + 1i) + (a + a2) * i = 0
z2 + -1z(1 + 1a + ai + 1i) + (a + a2) * i = 0
z2 + (1 * -1z + 1a * -1z + ai * -1z + 1i * -1z) + (a + a2) * i = 0

Reorder the terms:
z2 + (-1aiz + -1az + -1iz + -1z) + (a + a2) * i = 0
z2 + (-1aiz + -1az + -1iz + -1z) + (a + a2) * i = 0

Reorder the terms for easier multiplication:
z2 + -1aiz + -1az + -1iz + -1z + i(a + a2) = 0
z2 + -1aiz + -1az + -1iz + -1z + (a * i + a2 * i) = 0
z2 + -1aiz + -1az + -1iz + -1z + (ai + a2i) = 0

Reorder the terms:
ai + -1aiz + -1az + a2i + -1iz + -1z + z2 = 0

Solving
ai + -1aiz + -1az + a2i + -1iz + -1z + z2 = 0

Solving for variable 'a'.

The solution to this equation could not be determined.

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